Determination of the Equilibrium Constant of an Unknown
Ester Hydrolysis Reaction
Abstract
The experiments to follow determined that the equilibrium concentrations of the reaction: ester + water ↔ alcohol + acid, are equal to 0.0363 moles of ester, 0.2852 moles of water, and 0.0268 moles each of alcohol and acid. Using this information the equilibrium constant was determined to be 0.06938.
1. Introduction
In this lab the equilibrium constant, Kc, for the acid catalyzed reaction between an unknown ester and water to form an unknown alcohol and an unknown carboxylic acid was determined. The equation for the reaction is the following:
R1COOR2 + H2O ↔ R2OH + R1COOH (eq.1)
The symbol R represents a general hydrocarbon residue of some specified structure. The equilibrium concentrations were determined through a series of experiments where a known base, Sodium Hydroxide (NaOH), was titrated......
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